The windings of a gluon

Gluons are traditionally represented by a two dimensional projection of a helix. Actually close inspection of some pretty gluons reveals that it is usually not quite a helix. Hence the gluons in Axodraw are also not quite helices. In addition one may notice that the begin and end points deviate slightly from the regular windings. This makes it more in agreement with hand drawn gluons. When a gluon is drawn, one needs not only its begin and end points but there is an amplitude connected to this almost helix, and in addition there are windings. The number of windings is the number of curls that the gluon will have. Different people may prefer different densities of curls. This can effect the appearance considerably:

    \begin{center}
    \begin{picture}(330,100)(0,0)
    \Gluon(25,15)(25,95){5}{4}     \Text(25,7)[]{4 windings}
    \Gluon(95,15)(95,95){5}{5}     \Text(95,7)[]{5 windings}
    \Gluon(165,15)(165,95){5}{6}   \Text(165,7)[]{6 windings}
    \Gluon(235,15)(235,95){5}{7}   \Text(235,7)[]{7 windings}
    \Gluon(305,15)(305,95){5}{8}   \Text(305,7)[]{8 windings}
    \end{picture}
    \end{center}
This code results in:

\begin{picture}(330,100)(0,0)
\Gluon(25,15)(25,95){5}{4} \Text(25,7)[]{4 winding...
... windings}
\Gluon(305,15)(305,95){5}{8} \Text(305,7)[]{8 windings}
\end{picture}
The influence of the amplitude is also rather great. The user should experiment with it. There is however an aspect to the amplitude that should be discussed. For a straight gluon the amplitude can determine on which side the curls are. So does the direction of the gluon:
    \begin{center}
    \begin{picture}(325,100)(0,0)
    \Gluon(50,15)(50,95){5}{6}
    \Text(50,7)[]{amp $> 0$}  \Text(40,50)[]{$\uparrow$}
    \Gluon(125,95)(125,15){5}{6}
    \Text(125,7)[]{amp $> 0$} \Text(115,50)[]{$\downarrow$}
    \Gluon(200,15)(200,95){-5}{6}
    \Text(200,7)[]{amp $< 0$} \Text(190,50)[]{$\uparrow$}
    \Gluon(275,95)(275,15){-5}{6}
    \Text(275,7)[]{amp $< 0$} \Text(265,50)[]{$\downarrow$}
    \end{picture}
    \end{center}
The picture gets the following appearance:

\begin{picture}(325,100)(0,0)
\Gluon(50,15)(50,95){5}{6}
\Text(50,7)[]{amp $> 0$...
...15){-5}{6}
\Text(275,7)[]{amp $< 0$} \Text(265,50)[]{$\downarrow$}
\end{picture}
For straight gluons one does not need the option of the negative amplitude. It is however necessary for gluons on an arc segment. In that case the arc is always drawn in an anticlockwise direction. Hence the direction is fixed and only the amplitude is left as a tool for determining the side with the curls.